Best Possible Bounds for Yang Mean Using Generalized Logarithmic Mean

Mathematical Problems in Engineering, Apr 2016

We prove that the double inequality holds for all with if and only if and and find several sharp inequalities involving the trigonometric, hyperbolic, and inverse trigonometric functions, where is the unique solution of the equation on the interval , , and , and are the Yang, and th generalized logarithmic means of and , respectively.

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Best Possible Bounds for Yang Mean Using Generalized Logarithmic Mean

Hindawi Publishing Corporation Mathematical Problems in Engineering Volume 2016, Article ID 8901258, 7 pages http://dx.doi.org/10.1155/2016/8901258 Research Article Best Possible Bounds for Yang Mean Using Generalized Logarithmic Mean Wei-Mao Qian1 and Yu-Ming Chu2 1 School of Distance Education, Huzhou Broadcast and TV University, Huzhou 313000, China Department of Mathematics, Huzhou Teachers College, Huzhou 313000, China 2 Correspondence should be addressed to Yu-Ming Chu; Received 23 January 2016; Revised 16 March 2016; Accepted 28 March 2016 Academic Editor: Kishin Sadarangani Copyright © 2016 W.-M. Qian and Y.-M. Chu. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We prove that the double inequality 𝐿 𝑝 (𝑎, 𝑏) < 𝑈(𝑎, 𝑏) < 𝐿 𝑞 (𝑎, 𝑏) holds for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏 if and only if 𝑝 ≤ 𝑝0 and 𝑞 ≥ 2 and find several sharp inequalities involving the trigonometric, hyperbolic, and inverse trigonometric functions, where 𝑝0 = 0.5451 ⋅ ⋅ ⋅ is the unique solution of the equation (𝑝 + 1)1/𝑝 = √2𝜋/2 on the interval (0, ∞), 𝑈(𝑎, 𝑏) = (𝑎 − 𝑏)/[√2 arctan((𝑎 − 𝑏)/√2𝑎𝑏)], and 𝐿 𝑝 (𝑎, 𝑏) = [(𝑎𝑝+1 − 𝑏𝑝+1 )/((𝑝 + 1)(𝑎 − 𝑏))]1/𝑝 (𝑝 ≠ −1, 0), 𝐿 −1 (𝑎, 𝑏) = (𝑎 − 𝑏)/(log 𝑎 − log 𝑏) and 𝐿 0 (𝑎, 𝑏) = (𝑎𝑎 /𝑏𝑏 )1/(𝑎−𝑏) /𝑒 are the Yang, and 𝑝th generalized logarithmic means of 𝑎 and 𝑏, respectively. 1. Introduction Stolarsky [1] proved that the inequality For 𝑝 ∈ R and 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏, the 𝑝th generalized logarithmic mean 𝐿 𝑝 (𝑎, 𝑏) is defined by 𝑎𝑝+1 − 𝑏𝑝+1 { { ] [ { { { (𝑝 + 1) (𝑎 − 𝑏) { { { 𝑎 1/(𝑎−𝑏) 𝐿 𝑝 (𝑎, 𝑏) = { 1 ( 𝑎 ) , { 𝑏 { 𝑒 𝑏 { { { 𝑎−𝑏 { { , { log 𝑎 − log 𝑏 1/𝑝 , 𝑝 ≠ 0, −1, 𝑝 = 0, (1) 𝑝 = −1. It is well known that 𝐿 𝑝 (𝑎, 𝑏) is continuous and strictly increasing with respect to 𝑝 ∈ R for fixed 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏. Many classical bivariate means are the special case of the generalized logarithmic mean. For example, 𝐺(𝑎, 𝑏) = √𝑎𝑏 = 𝐿 −2 (𝑎, 𝑏) is the geometric mean, 𝐿(𝑎, 𝑏) = (𝑎 − 𝑏)/(log 𝑎−log 𝑏) = 𝐿 −1 (𝑎, 𝑏) is the logarithmic mean, 𝐼(𝑎, 𝑏) = (𝑎𝑎 /𝑏𝑏 )1/(𝑎−𝑏) /𝑒 = 𝐿 0 (𝑎, 𝑏) is the identric mean, and 𝐴(𝑎, 𝑏) = (𝑎 + 𝑏)/2 = 𝐿 1 (𝑎, 𝑏) is the arithmetic mean. Recently, the generalized logarithmic mean has been the subject of intensive research. 𝐿 𝑝 (𝑎, 𝑏) < 𝑀(2+𝑝)/3 (𝑎, 𝑏) (2) holds for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏 and 𝑝 ∈ (−2, −1/2) ∪ (1, ∞), and inequality (2) is reversed for 𝑝 ∈ (−∞, −2) ∪ (−1/2, 1), where 𝑀𝑟 (𝑎, 𝑏) = [(𝑎𝑟 + 𝑏𝑟 )/2]1/𝑟 (𝑟 ≠ 0) and 𝑀0 (𝑎, 𝑏) = √𝑎𝑏 is the 𝑟th power mean of 𝑎 and 𝑏. Yang [2] proved that the double inequality 𝐴 (𝑎, 𝑏) < 𝐿 𝑝 (𝑎, 𝑏) < 𝑀𝑝 (𝑎, 𝑏) (3) holds for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏 if 𝑝 > 1, and inequality (3) is reversed if 𝑝 < 0. In [3], the authors proved that the inequality 𝐿 𝑝 (𝑎, 𝑏) < 𝑎+𝑏 (𝑝 + 1) 1/𝑝 (4) holds for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏 and 𝑝 > 1. Li et al. [4] proved that the function 𝑝 󳨃→ 𝐿 𝑝 (𝑎, 𝑏)/𝐿 𝑝 (1 − 𝑎, 1 − 𝑏) is strictly increasing (decreasing) on R if 0 < 𝑎 < 𝑏 ≤ 1/2 (1/2 ≤ 𝑎 < 𝑏 < 1). In [5, 6], the authors proved that the function 𝑞 󳨃→ 𝐿 𝑞 (𝑎, 𝑏)/𝐿 𝑞 (𝑎, 𝑐) is strictly decreasing on R if 0 < 𝑎 < 𝑏 < 𝑐 and the function 𝑟 󳨃→ 𝐿 𝑟 (𝑑, 𝑑 + 𝜀)/𝐿 𝑟 (𝑑 + 𝛿, 𝑑 + 𝜀 + 𝛿) is strictly increasing on R for all 𝑑, 𝜀, 𝛿 > 0. 2 Mathematical Problems in Engineering Shi and Wu [7] proved that the double inequality (𝜆𝑏 + ((1 − 𝜆) /2) (𝑎 + 𝑏))𝑝+1 − (𝜆𝑎 + ((1 − 𝜆) /2) (𝑎 + 𝑏))𝑝+1 ] [ 𝜆 (𝑝 + 1) (𝑏 − 𝑎) for all 𝑏 > 𝑎 > 𝑐 > 0 and 0 < 𝜆 < 1 if 𝑝 > 1, and inequality (5) is reversed if 𝑝 ∈ (−1, 0) ∪ (0, 1). Long and Chu [8] and Matejı́čka [9] presented the best possible parameters 𝑝 = 𝑝(𝛼) and 𝑞 = 𝑞(𝛼) such that the double inequality 𝐿 𝑝 (𝑎, 𝑏) < 𝛼𝐴 (𝑎, 𝑏) + (1 − 𝛼) 𝐺 (𝑎, 𝑏) < 𝐿 𝑞 (𝑎, 𝑏) (6) holds for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏 and 𝛼 ∈ (0, 1/2) ∪ (1/2, 1). In [10], Qian and Long answered the question: what are the greatest value 𝑝 and the least value 𝑞 such that the double inequality 𝐿 𝑝 (𝑎, 𝑏) < 𝐺𝛼 (𝑎, 𝑏) 𝐻1−𝛼 (𝑎, 𝑏) < 𝐿 𝑞 (𝑎, 𝑏) (7) holds for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏 and 𝛼 ∈ (0, 1), where 𝐻(𝑎, 𝑏) = 2𝑎𝑏/(𝑎 + 𝑏) is the harmonic mean of 𝑎 and 𝑏. In [11, 12], the authors proved that the double inequalities 𝐿 𝑝1 (𝑎, 𝑏) < 𝑀 (𝑎, 𝑏) < 𝐿 𝑞1 (𝑎, 𝑏) , 𝐿 𝑝2 (𝑎, 𝑏) < 𝑇 (𝑎, 𝑏) < 𝐿 𝑞2 (𝑎, 𝑏) (8) hold for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏 if and only if 𝑝1 ≤ 𝑝1∗ , 𝑞1 ≥ 2, 𝑝2 ≤ 3, 𝑞2 ≥ 𝑞2∗ , where 𝑝1∗ = 1.843 ⋅ ⋅ ⋅ is the unique solution of the equation (𝑝 + 1)1/𝑝 = 2 log(1 + √2) on the interval (0, ∞), 𝑞2∗ = 3.152 ⋅ ⋅ ⋅ is the unique solution of the equation (𝑞 + 1)1/𝑞 = 𝜋/2 on the interval (0, ∞), 𝑀(𝑎, 𝑏) = (𝑎 − 𝑏)/[2 sinh−1 ((𝑎 − 𝑏)/(𝑎 + 𝑏))] is the NeumanSándor mean, and 𝑇(𝑎, 𝑏) = (𝑎 − 𝑏)/[2 arctan((𝑎 − 𝑏)/(𝑎 + 𝑏))] is the second Seiffert mean. In [13, 14], the authors presented the best possible parameters 𝑝1 = 𝑝1 (𝑞), 𝑝2 = 𝑝2 (𝑞), 𝜆 = 𝜆(𝛼), and 𝜇 = 𝜇(𝛼) such that the double inequalities 1/𝑞 𝐿 𝑝1 (𝑎, 𝑏) < [𝐿 (𝑎𝑞 , 𝑏𝑞 )] < 𝐿 𝑝2 (𝑎, 𝑏) , 𝐴 (𝑎, 𝑏) + 𝐺 (𝑎, 𝑏) 1−𝛼 𝐿 𝜆 (𝑎, 𝑏) < 𝐺𝛼 (𝑎, 𝑏) [ ] 2 (9) 1/𝑝 (𝑎 + 𝑏 − 𝑐)𝑝+1 − 𝑐𝑝+1 ] < 𝐿 𝑝 (𝑎, 𝑏) < [ (𝑝 + 1) (𝑎 + 𝑏 − 2𝑐) (5) Very recently, Yang [16] introduced the Yang mean 𝑈 (𝑎, 𝑏) = 𝑎−𝑏 √2 arctan ((𝑎 − 𝑏) /√2𝑎𝑏) (11) of two distinct positive real numbers 𝑎 and 𝑏 and proved that the inequalities 𝑃 (𝑎, 𝑏) < 𝑈 (𝑎, 𝑏) < 𝑇 (𝑎, 𝑏) , 𝐺 (𝑎, 𝑏) 𝑇 (𝑎, 𝑏) 𝑃 (𝑎, 𝑏) 𝑄 (𝑎, 𝑏) < 𝑈 (𝑎, 𝑏) < , 𝐴 (𝑎, 𝑏) 𝐴 (𝑎, 𝑏) 𝑄1/2 (𝑎, 𝑏) [ 2𝐺 (𝑎, 𝑏) + 𝑄 (𝑎, 𝑏) 1/2 ] < 𝑈 (𝑎, 𝑏) 3 < 𝑄2/3 (𝑎, 𝑏) [ 𝐺 (𝑎, 𝑏) + 𝑄 (𝑎, 𝑏) 1/3 ] , 2 (12) 𝐺 (𝑎, 𝑏) + 𝑄 (𝑎, 𝑏) < 𝑈 (𝑎, 𝑏) 2 2 𝐺 (𝑎, 𝑏) + 𝑄 (𝑎, 𝑏) 1/2 1 1/2 ) + 𝑄 (𝑎, 𝑏)] <[ ( 3 2 3 2 hold for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏, where 𝑄(𝑎, 𝑏) = √(𝑎2 + 𝑏2 )/2 is the quadratic mean of 𝑎 and 𝑏. The Yang mean 𝑈(𝑎, 𝑏) is the special case of the Seiffert type mean 𝑇𝑀,𝑞 (𝑎, 𝑏) = (𝑎 − 𝑏)/[𝑞 arctan((𝑎 − 𝑏)/(𝑞𝑀(𝑎, 𝑏)))] defined by Toader in [17], where 𝑀(𝑎, 𝑏) is a bivariate mean and 𝑞 is a positive real number. Indeed, 𝑈(𝑎, 𝑏) = 𝑇𝐺,√2 (𝑎, 𝑏). In [18, 19], the authors proved that the double inequalities 2 𝐺 (𝑎, 𝑏) + 𝑄 (𝑎, 𝑏) 𝑝 1 𝑝 [ ( ) + 𝑄 (𝑎, 𝑏)] 3 2 3 1/𝑝 2 𝐺 (𝑎, 𝑏) + 𝑄 (𝑎, 𝑏) 𝑞 1 𝑞 <[ ( ) + 𝑄 (𝑎, 𝑏)] 3 2 3 < 𝑈 (𝑎, 𝑏) 1/𝑞 , 21−𝜆 (𝐺 (𝑎, 𝑏) + 𝑄 (𝑎, 𝑏))𝜆 𝑄 (𝑎, 𝑏) + 𝐺 (𝑎, 𝑏) 𝑄𝜆 (𝑎, 𝑏) < 𝐿 𝜇 (𝑎, 𝑏) 21−𝜆 (𝐺 (𝑎, 𝑏) + 𝑄 (𝑎, 𝑏))𝜆 + 𝑄𝜆 (𝑎, 𝑏) hold for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏, 𝑞 > 0 with 𝑞 ≠ 1 and 𝛼 ∈ (0, 2/3) ∪ (2/3, 1). Gao et al. [15] provided the greatest value 𝛼 and the least value 𝛽 such that the double inequality 𝐿 𝛼 (𝑎, 𝑏) < 𝑃 (𝑎, 𝑏) < 𝐿 𝛽 (𝑎, 𝑏) 1/𝑝 (10) holds for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏, where 𝑃(𝑎, 𝑏) = (𝑎 − 𝑏)/[2 arcsin((𝑎 − 𝑏)/(𝑎 + 𝑏))] is the first Seiffert mean of 𝑎 and 𝑏. (13) < 𝑈 (𝑎, 𝑏) < 21−𝜇 (𝐺 (𝑎, 𝑏) + 𝑄 (𝑎, 𝑏))𝜇 𝑄 (𝑎, 𝑏) + 𝐺 (𝑎, 𝑏) 𝑄𝜇 (𝑎, 𝑏) , 21−𝜇 (𝐺 (𝑎, 𝑏) + 𝑄 (𝑎, 𝑏))𝜇 + 𝑄𝜇 (𝑎, 𝑏) 𝑀𝛼 (𝑎, 𝑏) < 𝑈 (𝑎, 𝑏) < 𝑀𝛽 (𝑎, 𝑏) hold for all 𝑎, 𝑏 > 0 with 𝑎 ≠ 𝑏 if and only if 𝑝 ≤ 𝑝0 , 𝑞 ≥ 1/5, 𝜆 ≥ 1/5, 𝜇 ≤ 𝑝1 , 𝛼 ≤ 2 log 2/(2 log 𝜋 − log 2), and 𝛽 ≥ 4/3, where 𝑝0 = 0.1941 ⋅ ⋅ ⋅ is the unique solution of the equation Mathematical Problems in Engineering 3 𝑝 log(2/𝜋)−log(1+21−𝑝 )+log 3 = 0 on the interval (1/10, (...truncated)


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Wei-Mao Qian, Yu-Ming Chu. Best Possible Bounds for Yang Mean Using Generalized Logarithmic Mean, Mathematical Problems in Engineering, 2016, 2016, DOI: 10.1155/2016/8901258