New Hermite-Hadamard Type Inequalities for -Times Differentiable and -Logarithmically Preinvex Functions
Hindawi Publishing Corporation
Abstract and Applied Analysis
Volume 2014, Article ID 725987, 11 pages
http://dx.doi.org/10.1155/2014/725987
Research Article
New Hermite-Hadamard Type Inequalities for π-Times
Differentiable and π -Logarithmically Preinvex Functions
Shuhong Wang1,2 and Ximin Liu1
1
2
School of Mathematical Sciences, Dalian University of Technology, Dalian 11602, China
College of Mathematics, Inner Mongolia University for Nationalities, Tongliao 028043, China
Correspondence should be addressed to Shuhong Wang;
Received 6 March 2014; Revised 27 June 2014; Accepted 29 June 2014; Published 20 July 2014
Academic Editor: Cristina Pignotti
Copyright Β© 2014 S. Wang and X. Liu. This is an open access article distributed under the Creative Commons Attribution License,
which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
The concept of s-logarithmically preinvex function is introduced, and by creating an integral identity involving an n-times
differentiable function, some new Hermite-Hadamard type inequalities for s-logarithmically preinvex functions are established.
1. Introduction
Throughout this paper, let R = (ββ, β), R+ = (0, β), N
denote the set of all positive integers, πΌ denote the interval in
R, and π΄ denote the set in Rπ , π β N.
Let us recall some definitions of various convex functions.
Definition 1. A function π : πΌ β R β R is said to be convex
if
π (ππ₯ + (1 β π) π¦) β€ ππ (π₯) + (1 β π) π (π¦)
(1)
holds for all π₯, π¦ β πΌ and π β [0, 1]. If inequality (1) reverses,
then π is said to be concave on πΌ.
Definition 2 (see [1]). A set π΄ β Rπ is said to be invex with
respect to the map π : π΄ Γ π΄ β Rπ , if for every π₯, π¦ β π΄ and
π‘ β [0, 1]
π¦ + π‘π (π₯, π¦) β π΄.
(2)
The invex set π΄ is also called a π-connected set.
It is obvious that every convex set is invex with respect to
the map π(π₯, π¦) = π₯ β π¦, but there exist invex sets which are
not convex (see [1], e.g.).
Definition 3 (see [1]). Let π΄ β Rπ be an invex set with respect
to π : π΄Γπ΄ β Rπ . For every π₯, π¦ β π΄, the π-path ππ₯V joining
the points π₯ and V = π₯ + π(π¦, π₯) is defined by
ππ₯V = {π§ | π§ = π₯ + π‘π (π¦, π₯) , π‘ β [0, 1]} .
(3)
Definition 4 (see [2]). Let π΄ β Rπ be an invex set with respect
to π : π΄ Γ π΄ β Rπ . A function π : π΄ β R is said to be
preinvex with respect to π, if for every π₯, π¦ β π΄ and π‘ β [0, 1]
π (π¦ + π‘π (π₯, π¦)) β€ π‘π (π₯) + (1 β π‘) π (π¦) .
(4)
The function π is said to be preincave if and only if βπ is
preinvex.
Every convex function is preinvex with respect to the map
π(π₯, π¦) = π₯ β π¦, but not conversely (see [2], e.g.).
Definition 5 (see [3]). Let π΄ β Rπ be an invex set with respect
to π : π΄ Γ π΄ β Rπ . The function π : π΄ β R+ on the set π΄
is said to be logarithmically preinvex with respect to π, if for
every π₯, π¦ β π΄ and π‘ β [0, 1]
π‘
1βπ‘
π (π¦ + π‘π (π₯, π¦)) β€ [π(π₯)] [π(π¦)]
.
(5)
For properties and applications of preinvex and logarithmically preinvex functions, please refer to [1β8] and closely
related references therein.
2
Abstract and Applied Analysis
The most important inequality in the theory of convex functions, the well known Hermite-Hadamardβs integral
inequality, may be stated as follows. Let πΌ β R and π, π β πΌ
with π < π. If π : [π, π] β πΌ β R is a convex function on
[π, π], then
π(
π
π (π) + π (π)
1
π+π
)β€
.
β« π (π₯) ππ₯ β€
2
πβπ π
2
(6)
If π is concave on [π, π], then inequality (6) is reversed.
Inequality (6) has been generalized by many mathematicians. Some of them may be recited as follows.
Theorem 6 (see [9, Theorem 2.2]). Let π : πΌ β R β R be a
differentiable mapping on πΌ and π, π β πΌ with π < π. If |πσΈ (π₯)|
is convex on [π, π], then
σ΅¨σ΅¨
σ΅¨σ΅¨
π
1
σ΅¨σ΅¨
σ΅¨σ΅¨ π (π) + π (π)
σ΅¨σ΅¨
σ΅¨σ΅¨
π
ππ₯
β
β«
(π₯)
σ΅¨σ΅¨
σ΅¨σ΅¨
2
π
β
π
π
σ΅¨
σ΅¨
σ΅¨σ΅¨ σΈ σ΅¨σ΅¨ σ΅¨σ΅¨ σΈ σ΅¨σ΅¨
(π β π) [σ΅¨σ΅¨σ΅¨π (π)σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨π (π)σ΅¨σ΅¨σ΅¨]
β€
.
8
(7)
Theorem 7 (see[10, Theorem 1]). Let πΌ β R and π, π β πΌ with
π < π. If π : [π, π] β πΌ β R is differentiable on [π, π] such that
|πσΈ (π₯)|π is a convex function on [π, π] for π β₯ 1, then
σ΅¨σ΅¨
σ΅¨σ΅¨
π
1
σ΅¨σ΅¨ π (π) + π (π)
σ΅¨σ΅¨
σ΅¨σ΅¨
σ΅¨σ΅¨
π
ππ₯
β
β«
(π₯)
σ΅¨σ΅¨
σ΅¨σ΅¨
2
π
β
π
π
σ΅¨
σ΅¨
σ΅¨σ΅¨ σΈ σ΅¨σ΅¨π σ΅¨σ΅¨ σΈ σ΅¨σ΅¨π 1/π
π β π [ σ΅¨σ΅¨σ΅¨π (π)σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨π (π)σ΅¨σ΅¨σ΅¨ ]
β€
.
4
2
[
]
Theorem 10 (see [4, Theorem 4.3]). Let π΄ β R be an open
invex set with respect to π : π΄ Γ π΄ β R and π, π β π΄ with
π(π, π) > 0 for all π =ΜΈ π. Suppose that π : π΄ β R is a twice
differentiable function on π΄ and |πσΈ σΈ (π₯)| is preinvex on π΄. If
π > 1 and πσΈ σΈ is integrable on the π-path πππ for π = π + π(π, π),
then
σ΅¨σ΅¨
σ΅¨σ΅¨ π (π) + π (π + π (π, π))
π+π(π,π)
1
σ΅¨σ΅¨
σ΅¨σ΅¨
σ΅¨σ΅¨
σ΅¨σ΅¨
π
ππ₯
β
β«
(π₯)
σ΅¨σ΅¨
σ΅¨σ΅¨
2
π
π)
(π,
π
σ΅¨
σ΅¨
2
[π(π, π)] 1 1/π σ΅¨σ΅¨ σΈ σΈ σ΅¨σ΅¨π σ΅¨σ΅¨ σΈ σΈ σ΅¨σ΅¨π 1/π
β€
( ) [σ΅¨σ΅¨σ΅¨π (π)σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨π (π)σ΅¨σ΅¨σ΅¨ ] .
12
2
Theorem 11 (see [12, Theorem 3.1]). For π β N and π β₯ 2, let
π΄ β R be an open invex set with respect to π : π΄ Γ π΄ β R and
π, π β π΄ with π(π, π) > 0 for all π =ΜΈ π. Suppose that π : π΄ β R
is an π-times differentiable function on π΄ and π(π) is integrable
on the π-path πππ for π = π + π(π, π). If |π(π) |π is preinvex on π΄
for π β₯ 1, then
σ΅¨σ΅¨ π (π) + π (π + π (π, π))
π+π(π,π)
1
σ΅¨σ΅¨
σ΅¨σ΅¨
π (π₯) ππ₯
β
β«
σ΅¨σ΅¨
2
π (π, π) π
σ΅¨
[π (π, π)] (1 β π)
4 [(π + 1)!]
π=1
(8)
σ΅¨σ΅¨
σ΅¨
Γ [π(π) (π) + (β1)π π(π) (π + π (π, π))] σ΅¨σ΅¨σ΅¨σ΅¨
σ΅¨σ΅¨
σ΅¨π
σ΅¨σ΅¨
σ΅¨π(π, π)σ΅¨σ΅¨σ΅¨ (π β 1)1β1/π
β€ σ΅¨
4 [(π + 1)!] (π + 2)1/π
σ΅¨
σ΅¨π/(πβ1)
σ΅¨
σ΅¨π/(πβ1) 1β1/π
Γ {[σ΅¨σ΅¨σ΅¨σ΅¨πσΈ (π)σ΅¨σ΅¨σ΅¨σ΅¨
+ 3σ΅¨σ΅¨σ΅¨σ΅¨πσΈ (π)σ΅¨σ΅¨σ΅¨σ΅¨
]
σ΅¨
σ΅¨π
σ΅¨
σ΅¨π 1/π
+ [(π2 β 2)σ΅¨σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨σ΅¨ + πσ΅¨σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨σ΅¨ ] } .
(9)
σ΅¨
σ΅¨π/(πβ1) σ΅¨σ΅¨ σΈ σ΅¨σ΅¨π/(πβ1) 1β1/π
+ [3σ΅¨σ΅¨σ΅¨σ΅¨πσΈ (π)σ΅¨σ΅¨σ΅¨σ΅¨
+ σ΅¨σ΅¨σ΅¨π (π)σ΅¨σ΅¨σ΅¨
]
}.
Theorem 9 (see [6]). Let π΄ β R be an open invex set with
respect to π : π΄ Γ π΄ β R and π, π β π΄ with π(π, π) > 0 for
all π =ΜΈ π. If π : π΄ β R+ is a preinvex function on π΄, then the
following inequality holds:
π(
π+π(π,π)
2π + π (π, π)
1
π (π₯) ππ₯
)β€
β«
2
π (π, π) π
π (π) + π (π)
β€
.
2
(12)
σ΅¨
σ΅¨π
σ΅¨
σ΅¨π 1/π
Γ {[πσ΅¨σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨σ΅¨ + (π2 β 2)σ΅¨σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨σ΅¨ ]
σ΅¨σ΅¨
σ΅¨σ΅¨
π
π+π
1
σ΅¨σ΅¨
σ΅¨σ΅¨
σ΅¨σ΅¨π (
σ΅¨σ΅¨
π
ππ₯
)
β
β«
(π₯)
σ΅¨σ΅¨
σ΅¨σ΅¨
2
π
β
π
π
σ΅¨
σ΅¨
1/π
πβπ
4
(
)
16 π + 1
π
πβ1
+β
Theorem 8 (see [11, Theorem 2.3]). Let π : πΌ β R β R
be differentiable on πΌ, π, π β πΌ with π < π and π > 1. If
|πσΈ (π₯)|π/(πβ1) is convex on [π, π], then
β€
(11)
(10)
Theorem 12 (see [13, Theorem 5]). For π β N and π β₯ 2, let
π΄ β R be an open invex set with respect to π : π΄ Γ π΄ β R and
π, π β π΄ with π(π, π) > 0 for all π =ΜΈ π. Suppose that π : π΄ β R
is a function such that π(π) exits on π΄ and π(π) is integrable on
[π, π + π(π, π)]. If |π(π) |π is logarithmically preinvex on π΄ for
π β₯ 1, then we have the inequality
σ΅¨σ΅¨
π+π(π,π)
σ΅¨σ΅¨ π (π) + π (π + π (π, π))
1
σ΅¨σ΅¨
π (π₯) ππ₯
β
β«
σ΅¨σ΅¨
2
π (π, π) π
σ΅¨σ΅¨
σ΅¨σ΅¨
π
πβ1
σ΅¨σ΅¨
(β1)π (π β 1) (π (π, π)) (π)
ββ
π (π + π (π, π))σ΅¨σ΅¨σ΅¨
σ΅¨σ΅¨
2
+
1)!
(π
π=2
σ΅¨
π
β€
(π(π, π)) π β 1 1β1/π
1/π
[πΈ1 (π, π)] ,
(
)
2π!
π+1
(13)
Abstract and Applied Analysis
3
(π₯βπ)/(π(π,π))
where
Γ [β«
0
πΈ1 (π, π)
σ΅¨
σ΅¨
σ΅¨
σ΅¨
σ΅¨π
σ΅¨
(β1)π π! {π [ln (σ΅¨σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨σ΅¨) β ln (σ΅¨σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨σ΅¨)] + 2} σ΅¨σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨σ΅¨
=
σ΅¨
σ΅¨
σ΅¨ π+1
σ΅¨
ππ+1 [ln (σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨) β ln (σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨)]
σ΅¨π
σ΅¨
2σ΅¨σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨σ΅¨
σ΅¨σ΅¨ (π) σ΅¨σ΅¨π
β
σ΅¨
σ΅¨
σ΅¨ β π!σ΅¨σ΅¨σ΅¨π (π)σ΅¨σ΅¨σ΅¨
σ΅¨
π [ln (σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨) β ln (σ΅¨σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨σ΅¨)]
σ΅¨
σ΅¨
σ΅¨
σ΅¨
π (β1)π {π [ln (σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨) β ln (σ΅¨σ΅¨π(π) (π)σ΅¨σ΅¨ (...truncated)