and ON SOME NEW DOUBLE SEQUENCE SPACES OF INVARIANT MEANS DEFINED BY ORLICZ FUNCTIONS and VAKEEL A. KHAN AND SABIHA TABASSUM
C o m m u n .Fa c .S c i.U n iv .A n k .S e rie s A 1
Vo lu m e 6 0 , N u m b e r 2 , P a g e s 1 1 –1 9 (2 0 1 1 )
IS S N 1 3 0 3 –5 9 9 1
and
ON SOME NEW DOUBLE SEQUENCE SPACES OF INVARIANT
MEANS DEFINED BY ORLICZ FUNCTIONS
and VAKEEL A. KHAN AND SABIHA TABASSUM
Abstract. The sequence space BV was introduced and studied by Mursaleen[14]. In this paper we extend BV to 2 BV (p; r; s) and study some
properties and inclusion relations on this space.
1. Introduction
Let l1 ; and c denote the Banach spaces of bounded and convergent sequences
x = (xi ), with complex terms, respectively, normed by kxk1 = sup jxi j, where
i
i 2 N: Let be an injection of the set of positive integers N into itself having no
…nite orbits that is to say, if and only if, for all i = 0; j = 0; j (i) 6= i and T be the
1
operator de…ned on l1 by (T (xi )1
i=1 ) = (x (i) )i=1 :
A continuous linear functional
-mean if and only if
on l1 is said to be an invariant mean or
(1) (x) 0; when the sequence x = (xi ) has xi 0 for all i;
(2) (e) = 1; where e = f1; 1; 1; :::::::g and
(3) (x (i) ) = (x) for all x 2 l1 :
If x = (xi ) write T x = (T xi ) = (x (i) ): It can be shown that
V =
x = (xi ) :
1
X
tm;i (x) = L uniformly in i; L =
lim x
(1)
m=1
where m
o; i > 0:
Received by the editors Agu. 01, 2011, Accepted: Dec. 26, 2011.
2000 Mathematics Subject Classi…cation. 46E30, 46E40, 46B20.
Key words and phrases. Invariant means, double sequence spaces, Orlicz Function.
c 2 0 1 1 A n ka ra U n ive rsity
11
12
VAKEEL A. KHAN AND SABIHA TABASSUM
1
tm;i (x) =
xi + x (i) + :::: + x m (i)
m+1
and t 1;i = 0
(2)
m
. Where
(i) denote the mth iterate of (i) at i: In the case is the translation
mapping, (i) = i + 1 is often called a Banach limit and V ; the set of bounded
sequences of all whose invariant means are equal, is the set of almost convergent
sequence. Subsequently invariant means have been studied by Ahmad and Mursaleen[1], Mursaleen[12,13], Raimi[15] and many others.
The concept of paranorm is closely related to linear metric spaces. It is generalization of that of absolute value. Let X be a linear space. A Paranorm is a
function g : X ! R which satis…es the following axioms: for any x; y; x0 2 X,
; 0 2 C,
(i) g( ) = 0;
(ii) g(x) = g( x);
(iii) g(x + y) g(x) + g(y)
(iv) the scalar multiplication is continuous, that is
! 0 , x ! x0 imply
x ! 0 x0 :
Any function g which satis…es all the condition (i)-(iv) together with the condition
(v) g(x) = 0 if only if x = ,
is called a Total Paranorm on X and the pair (X; g) is called Total paranormed
space. It is well known that the metric of any linear metric space is given by some
total paranorm (cf.[18],Theorm 10.42,p183])
An Orlicz Function is a function M : [0; 1) ! [0; 1) which is continuous,
nondecreasing and convex with M (0) = 0, M (x) > 0 for x > 0 and M (x) ! 1,
as x ! 1. If convexity of M is replaced by M (x + y) M (x) + M (y) then it is
called Modulus function.
An Orlicz function M satis…es the 2
exist constant k 2 and u0 > 0 such that
M (2u)
whenever juj
condition (M 2
2 for short ) if there
KM (u)
u0 .
1 The second author is supported by Maulana Azad National Fellowship under the University
Grants Commision of India.
ON SOM E NEW DOUBLE SEQUENCE SPACES OF INVARIANT M EANS
13
An Orlicz function M can always be represented in the integral form
Rx
M (x) = q(t)dt; where q known as the kernel of M; is right di¤erentiable for
0
t
0; q(t) > 0 for t > 0; qis non-decreasing and q(t) ! 1 as t ! 1:
Note that an Orlicz function satis…es the inequality
M ( x)
M (x) for all
with 0 <
< 1;
since M is convex and M (0) = 0:
W.Orlicz used the idea of Orlicz function to construct the space (LM ): Lindesstrauss and Tzafriri [9] used the idea of Orlicz sequence space;
lM :=
x2w:
1
X
M
jxk j
k=1
< 1; for some
which is Banach space with the norm the norm
1
X
jxk j
kxkM = inf
>0:
M
>0
1 :
k=1
The space lM is closely related to the space lp , which is an Orlicz sequence space
with M (x) = xp for 1 p < 1:
Orlicz functons have been studied by V.A.Khan[3,5,6,7,8] and many others.
Throughout a double sequence is denoted by x = (xij ):A double sequence is a
double in…nite array of elements xij 2 R for all i; j 2 N: Let 2 l1 and 2 c denote the
Banach spaces of bounded and convergent double sequence x = (xi;j ) respectively.
Doube sequence spaces have been studied by Moricz and Rhoads[11], E.Savas and
R.F.Patterson[16], V.A.Khan[4] and many others.
Let
l
by
2 1
be an injection having no …nite orbits and T be the operator de…ned on
1
T ((xi;j )1
i;j=1 ) = (x (i;j) )i;j
The idea of -convergence for double sequences has recently been introduced in [2]
and further studied by Mursaleen and Mohiuddine [12].
For double sequences,
1 X
1
X
V
=
x
=
(x
)
:
tmnpq (x) = L uniformly in p; q; L =
lim x see[16]
2
i;j
m=1 n=1
(3)
tmnpq (x) =
1 X
1
X
1
x i (p); j (q) ; p; q = 0; 1; 2:::
(m + 1)(n + 1) i=1 j=1
(4)
14
VAKEEL A. KHAN AND SABIHA TABASSUM
t0;0;p;q (x)
=
xpq ; t 1;0;p;q (x) = xp 1;q (x); t0; 1;p;q (x)
=
xp;q 1 ; t 1; 1;p;q (x) = xp 1;q 1 ;
and x i (p); j (q) = 0 for all i or j or both negative.
A double sequence space E is said to be solid if ( i;j xi;j ) 2 E, whenever
(xi;j ) 2 E, for all double sequences ( i;j ) of scalars with j i;j j 1; for all i; j 2 N:
Let
K = f(ni ; kj ) : i; j 2 N; n1 < n2 < n3 < :::: and k1 < k2 < k3 < :::g
N
N
and E be a double sequence space. A K-step space of E is a sequence space
E
K = f( i;j xi;j ) : (xi;j ) 2 Eg:
A canonical pre-image of a sequence (xni ;kj ) 2 E is a sequence (bn;k ) 2 E de…ned
as follows:
(
ank if (n; k) 2 K;
bnk =
0 otherwise :
A canonical pre-image of step space
elements in E
K:
E
K is a set of canonical pre-images of all
A double sequence space E is said to be monotone if it contains the canonical
pre-images of all its step spaces.
A double sequence space E is said to be symmetric if (xi;j ) 2 E implies
(x (i); (j) ) 2 E; where is a permutation of N:
2.
Main Results
Lemma 1 A sequence space E is solid implies E is monotone.
Mursaleen[14] de…ned the sequence space
BV = fx 2 l1 :
where
X
m
j m;i (x)j < 1; uniformly in ig;
m;i (x) = tm;i (x)
assuming that tm;i (x) = 0 for m = 1
A straightforward calculation shows that
tm 1;i (x)
(5)
ON SOM E NEW DOUBLE SEQUENCE SPACES OF INVARIANT M EANS
m;n (x) =
We de…ne
2 BV
8
<
:
1
m(m+1)
n[xn (i)
xn 1 (i)] (m
1)
(6)
n=1
xi (m = 0):
= fx 2 2 l1 :
where
mnpq (x) =
m
P
15
X
m;n
j mnpq (x)j < 1; uniformly in p and qg;
8
m P
n
P
>
1
>
ij[x i (p); j (q)
>
m(m+1)n(n+1)
<
i=1 j=1
(7)
x i 1 (p); j (q)
x i (p); j 1 (q) + x i 1 (p); j 1 (q) ] (m; n
>
>
>
:x m or n or both zero :
(see[12])
1)
(8)
ij
Let M be an Orlicz function, p = (pi ) be any sequence of strictly positive
real numbers and r 0. V.A.Khan[5] de…ned the following sequence space:
BV (M; p; r) =
x = (xi ) :
1
X
j m;i (x)j
1
M
r
m
m=1
uniformly in i and for some
pi
< 1;
>0 :
Let p = (pij ) be any double sequence of strictly positive real numbers a (...truncated)