The limb deformation of the compound bow
Meccanica (2017) 52:1475–1483
DOI 10.1007/s11012-016-0485-0
The limb deformation of the compound bow
M. Tiermas
Received: 24 February 2016 / Accepted: 3 July 2016 / Published online: 11 July 2016
Ó The Author(s) 2016. This article is published with open access at Springerlink.com
Abstract A model of the archery round-wheel
compound bow with a more realistic limb deformation
is introduced. The model is based on the former
compound bow model of the author with the supposition that the elastic limb deformation is consistent
with the Euler–Bernoulli equation. The Young’s
modulus of an example bow limb is determined. The
model is compared to the experimental data and to the
former model which uses the modified Hickman
approximation for the bow limbs. The effects of the
shape of the limb on the force-draw curve of the
compound bow are also considered. The model
presented here may be used when designing or
adjusting the limbs of the compound bow. An
approximation for the path of the limb tip for the
straight limb of uniform bending stiffness for small
deformations is also derived.
Keywords Compound bow Elastic deformation
Force-draw curve Eccentric wheel
M. Tiermas (&)
Department of Physics, University of Helsinki, Helsinki,
Finland
e-mail:
1 Introduction
The compound bow, which was invented by Claude
Lapp in 1938 [1], has become a popular instrument
among the bow hunters and sportsmen. Yet, the
mechanical action of the compound bow has not been
investigated until quite recently. In the earlier studies
[2–5] concerning compound bows the limb of the bow
has been treated as a straight rod, which bends only on
one point, which is either at the bottom of the limb or
at some distance from the limb bottom. This approximation is the motivation of this paper.
Hickman introduced a simple model of the traditional long bow in [6], where he also noticed that the
limb bends in the arc of circle. If the length of the limb
is L, he also showed that the path made by the limb tip
is an arc of the circle whose radius is 3L/4 and whose
center is located at a distance of 3L/4 from the tip of
the undeflected limb. This idea combined with the
Hooke’s law for the force acting on the tip of the limb
is the basis of his long bow model. The Hickman
model is confirmed by Tuijn and Kooi [7], and its
modified version is also included in the compound
bow model by the author [5].
The Hickman model was overtaken by Kooi in [8],
where the deformation of the limb of the bow with or
without recurve is thoroughly investigated. As a result,
the initial shape and also the possible length-dependent bending stiffness of the limb can be taken into
account. This kind of elastic limb bending is more
realistic and also offers a possibility for further
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Meccanica (2017) 52:1475–1483
generalizations. The aim of this paper is to insert this
elastic bending in the former model of the compound
bow presented in [5].
eccentric system is fixed on the other end of the limb.
Let us call the axle point T ¼ ðxðLÞ; y(L)) of this
eccentric system as the tip of the limb, as noted in
Fig. 1. Let us also introduce the angle
2 Formulation of the problem
k ¼ x xU
At first, we shall follow the theory of the static
deformation of the bow limb as introduced by Kooi
[8]. Let us assume that the limbs of the compound bow
are inextensible, they are symmetric as in [5, 8], and
can be represented by an elastic line of zero thickness.
Then it will be sufficient to consider the upper part of
the bow only. Let Ltot be the total length of the limb
measured from the riser end (the bottom) of the limb to
the axle point along the limb. As a part of the limb is
inside the modified part of the riser (the limb pocket),
let L be the length of the free (elastic) limb measured
from the point where the limb touches the riser to the
axle point along the limb. Let us assume that the part of
the limb which is inside the limb pocket is straight and
rigid. This rigid part of length Ltot L is also seen in
Fig.1 as the line GO.
Let O ¼ ðxð0Þ; yð0ÞÞ be the point where the free
limb meets the limb pocket. Let us call the point G in
Fig. 1 as the bottom of the limb, whereas the point O
may be called as the bottom of the free limb. The
where x is the angle of the infinitesimal segment of the
limb with respect to the vertical line and xU the angle
of the infinitesimal segment of the limb without the
string (undeflected limb) with respect to the vertical
line. There are also two geometric conditions,
dx
¼ sinðk þ xU Þ
dl
ð2Þ
dy
¼ cosðk þ xU Þ
dl
ð3Þ
where x and y are the Cartesian x- and y-coordinates of
the infinitesimal segment of the limb measured from
the bottom of the free limb towards the tip of the limb,
and l the length coordinate along the limb measured
from the bottom of the free limb with length L towards
the tip of the limb. The boundary conditions at l ¼ 0 are
kð0Þ ¼ xð0Þ ¼ yð0Þ ¼ 0
123
ð4Þ
Let us assume the Euler–Bernoulli equation for the
elastic line is valid. With the help of geometrics and
the Euler–Bernoulli equation, the following equation
can be derived,
W
Fig. 1 The upper part of the compound bow in drawn position
with related variables and forces. The size of the wheel system is
exaggerated. In balance, the supporting force K prevents the
limb from moving. The force K acting on the limb tip T is the
sum of components F s , F cl and F cu . The line segment GO is the
rigid part of the limb inside the limb pocket, whereas the curve
OT is the free limb. Note that the angle a is here negative
ð1Þ
dk
¼ K ððb xÞ cos s y sin sÞ
dl
ð5Þ
where W is the bending stiffness of the limb, K the
absolute value of the total force K acting on the tip of
the limb, s the angle between K and the vertical line,
and b the distance between the bottom of the free limb
and the point where the line that goes via the tip of the
limb and is parallel to K meets the vertical line that
goes via the bottom of the free limb. For the details of
Eqs. (1)–(5), the reader is kindly asked to examine the
paper [8], where the deformation of the conventional
bow (with or without recurve) is presented elaborately.
Now our problem differs from [8], for the
unknowns in the group of Eqs. (1)–(5) are K and b.
Also we must find s and the respective limb tip
coordinates yL ¼ yðLÞ and xL ¼ xðLÞ.
In [5], it was supposed that the limb bends as in
Hickman model with a slight modification, which is
Meccanica (2017) 52:1475–1483
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quite different case as here. However, we can still use
the compound bow model introduced in [5] in order to
find the limb tip y-coordinate and the angle s, for these
values can be calculated without the Hickman
assumption. From Fig. 1 we find that the y-coordinate
of the limb tip with respect to the bottom of the free
limb is
e g
yR ¼
þ ðLtot LÞ cos hU
ð6Þ
2
2
where e is the distance between the axle points of the
upper and the lower limbs, g the length of the riser
measured from the bottom of the upper limb to th (...truncated)